tentukan nilai X dari persamaan persamaan berikut ! a.8 ( x + 2 ) = 20 b.1/2x+ 6=1/4x - 7 C. 1/3 x +1/4 = 1/2x-1/3 Minta bantuan nya !!!

a.
[tex]8(x + 2) = 20 \\ 8x + 16 = 20 \\ 8x = 4 \\ x = \frac{4}{8} = \frac{1}{2} [/tex]
b.
[tex] \frac{1}{2} x + 6 = \frac{1}{4} x - 7 \\ \frac{1}{2} x - \frac{1}{4} x = - 7 - 6 \\ \frac{2 - 1}{4}x = - 13 \\ \frac{1}{4} x = - 13 \\x = - 13(4) = - 52[/tex]
c.
[tex] \frac{1}{3} x + \frac{1}{4} = \frac{1}{2} x - \frac{1}{3} \\ \frac{1}{3} x - \frac{1}{2} x = - \frac{1}{3} - \frac{1}{4} \\ \frac{2 - 3}{6} x = \frac{ - 4 - 3}{12} \\ \frac{1}{6} x = - \frac{7}{12} \\ x = - \frac{7}{12} \times 6 = - \frac{42}{12} = - \frac{21}{6} = - 3 \frac{3}{6} [/tex]