Bantu nomor 1 sama 2?

No 1
1/2 log (x^2 + 2x ) < -3
1/2 log (x^2 + 2x) < 1/2 log 1/2 ^ -3
X^2 + 2x < 1/2 ^ -3
X^2 + 2x < 1 / (1/8)
x^2 + 2x < 8
x^2 + 2x - 8 < 0
(x + 4) (x -2) < 0
Batas grafik selangnya
x = -4 dan x = 2
Nilai x yg memenuhi
-4 < x < 2

No. 2
(x-2) log (8 -x) > 2
(x-2) log ( 8 -x) > (x-2) log (x-2)^2
8-x > (x-2)^2
8-x > x^2 - 4x + 4
-x^2 + 3x +4 > 0
x^2 -3x -4 < 0
(x + 1) (x-4) < 0
Batas selang
x = -1 dan x = 4
Nilai x yg memenuhi
-1 < x < 4

2). x-2log(8-x)>2
log8-x>(x-2)^2
8-x>x^2-2x-2x+4
8-x>x^2-4x+4
x^2-4x+x+4-8>0
x^2-3x-4>0
(x-4) (x+1) >0

x=4
x=-1

++++------—--++++++
-1. 4

hp{x|x<-1 atau x>4 (E)