Simpangan baku dari sekelompok data tunggal 7, 3, 5, 4, 6, 5 adalah..

jawab

data 7 , 3, 5, 4, 6, 5
n = 6
jumlah = 7+3+5+4+6+5 = 30
x = 30/6 = 5

S = √ [ (5-7)² +(5-3)² +(5-5)² +(5 -4)² +(5-6)²+(5-5)² ] /(6)
S = √ (4+4+0+1+1+0) /(6)
S = √(10/(6)
S = √5/3
S = 5/3 √15