Tentukan persamaan garis melalui titik (2, -3) tegak lurus garis 3x + 9y = 5

Kelas 8 Matematika
Bab 3 - Persamaan Garis

ax + by = c, tegak lurus, (p, q)
bx - ay = bp - aq

3x + 9y = 5, tegak lurus, (2, - 3)
9x - 3y = 9 . 2 - 3 . (-3)
9x - 3y = 18 + 9
9x - 3y = 27
3x - y = 9

M = - 3/9 = - 1/2
y-y1 = M (x-x1)
y+3= - 1/2(x-2)
2y+6=x-2
2y-x+8=0