4^x-2 =√8^2x-2 Bentuk x=....?

[tex]4 {}^{x - 2} = \sqrt{8 {}^{2x - 2} } [/tex]
[tex]2 {}^{2x - 4} = 2 {}^{ \frac{3(2x - 2)}{2} } [/tex]
[tex]2 {}^{2x - 4} = 2 {}^{ \frac{3 \times 2(x - 1)}{2} } [/tex]
[tex]2 {}^{2x - 4} = 2 {}^{ {}^{3(x - 1)} } [/tex]
[tex]2 {}^{2x - 4} = 2 {}^{3x - 3} [/tex]
✐ Karna basisnya sama, tinggal hitung pangkatnya saja

[tex]2x - 4 = 3x - 3 \\ 2x - 3x = - 3 + 4 \\ - x = 1 \\ maka \\ \\ x = - 1[/tex]