jika p= 1/4+ 1/6+1/16+1/64+1/256+...maka nilai p=

p = 1/6 + (1/4 + 1/16 + 1/64 + ...)
= 1/6 + ((1/4)/(1 - 1/4))
= 1/6 + ((1/4)/(3/4))
= 1/6 + 1/3
= 1/2

Merupakan deret tak hingga dengan a = 1/4 dan r = 1/4
[tex]\displaystyle S_{\infty}=\frac{a}{1-r} = \frac{\frac{1}{4}}{1-\frac{1}{4}}=\frac{\frac{1}{4}}{\frac{3}{4}}=\frac{1}{3}[/tex]