Matematika

Pertanyaan

tolong dijawab no. 1-6!! please pake cara!
tolong dijawab no. 1-6!! please pake cara!

2 Jawaban

  • 1) (x + 6) (x + 3) = x(x + 8)
    x² + 9x + 18 = x² + 8x
    x² - x² + 9x - 8x - 18 = 0
    x - 18 = 0
    x = 18

    2) (x + 8) (x - 5) = x(x - 2)
    x² + 3x - 40 = x² - 2x
    x² - x² + 3x + 2x - 40 = 0
    5x - 40 = 0
    5x = 40
    x = 40 : 5
    x = 8

    3) (6x - 5) (x + 3) = 2x(3x + 4)
    6x² + 18x - 5x - 15 = 6x² + 8x
    6x² - 6x² + 13x - 8x - 15 = 0
    5x = 15
    x = 15 : 5
    x = 3

    4) (5x + 7) (x - 2) = 5x(x - 1)
    5x² - 10x + 7x - 14 = 5x² - 5x
    5x² - 5x² - 3x + 5x - 14 = 0
    2x = 14
    x = 14 : 2
    x = 7

    5) (x + 2) (x+ 4) = (x + 3) (x + 5)
    x² + 6x + 8 = x² + 8x + 15
    x² - x² + 6x - 8x + 8 - 15 = 0
    -2x - 7 = 0
    2x = -7
    x = -7/2

    6) (x - 7) (x - 2) = (x + 9) (x - 6)
    x² - 9x + 14 = x² + 2x - 54
    x² - x² - 9x - 2x + 14 + 54 = 0
    -11x + 68 = 0
    11x = 68
    x = 68/11

  • [tex]1. \\ (x + 6)(x + 3) = x(x + 8) \\ {x}^{2} + 3x + 6x + 18 = {x}^{2} + 8x \\ {x}^{2} - {x}^{2} + 3x + 6x + 18 = 8x \\ 3x + 6x + 18 = 8x \\ 9x + 18 = 8x \\ 9x - 8x = - 18 \\ x = - 18 \\ \\ 2. \\ (x + 8)(x - 5) = x(x - 2) \\ {x}^{2} - 5x + 8x - 40 = {x}^{2} - 2x \\ {x}^{2} - {x}^{2} - 5x + 8x - 40 = - 2x\\ - 5x + 8x - 40 = - 2x \\ 3x - 40 = - 2x \\ 3x + 2 x = 40 \\ 5x = 40 \\ x = 8 \\ \\ 3. \\ (6x - 5)(x + 3) = 2x(3x + 4) \\ {6x}^{2} + 18x - 5x - 15 = 6 {x}^{2} + 8x \\ 6 {x}^{2} - 6 {x}^{2} + 18x - 5x - 15 = 8x \\ 18x - 5x - 15 = 8x \\ 13x - 15 = 8x \\ 13x - 8x = 15 \\ 5x = 15 \\ x = 3 \\ \\ 4. \\ (5x + 7)(x - 2) = 5x(x - 1) \\ 5 {x}^{2} - 10x + 7x - 14 = 5 {x}^{2} - 5x \\ 5 {x}^{2} - 5 {x}^{2} - 10x + 7x - 14 = - 5 {x}^{2} \\ - 10x + 7x - 14 = - 5x \\ - 3x - 14 = - 5x \\ - 3x + 5x = 14 \\ 2x = 14 \\ x = 7 \\ \\ 5. \\ (x + 4)(x + 2) = (x + 9)(x - 6) \\ {x}^{2} + 2x + 4x + 8 = {x}^{2} - 6x + 9x - 54 \\ {x}^{2} - {x}^{2} + 2x + 4x + 8 = - 6x + 9x - 54 \\ 2x + 4x + 8 = - 6x + 9x - 54 \\ 6x + 8 = 3x - 54 \\ 6x - 3x = - 54 - 8 \\ 3x = - 62 \\ x = - \frac{62}{3} \\ x = - 20 \frac{2}{3} \\ \\ 6. \\ (x - 7)(x - 2) = (x + 9)(x - 6) \\ {x}^{2} - 2x - 7x + 14 = {x}^{2} - 6x + 9x - 54 \\ {x}^{2} - {x}^{2} - 2x - 7x + 14 = - 6x + 9x - 54 \\ - 2x - 7x + 14 = - 6x + 9x - 54 \\ - 9x + 14 = 3x - 54 \\ - 9x - 3x = - 54 - 14 \\ - 12x = - 68 \\ x = \frac{17}{3} \\ x = 5 \frac{2}{3} [/tex]