Matematika

Pertanyaan

Simpangan kuartil dari data 4,5,2,6,4,8,8,9,6,7,8 adakah

1 Jawaban

  • Q1 =x1/4. (n+1)
    =x1/4. (11+1)
    = x1/4. 12
    =x3
    =4

    Q2 = x1/2. (n+1)
    =x1/2. (11+1)
    = x1/2. 12
    =x6
    =6

    Q3 = x3/4. (n+1)
    =x3/4. (11+1)
    =x3/4. 12
    =x9
    =8

    Qd= 1/2 (Q3-Q1)
    =1/2 (8-4)
    =1/2 (4)
    =2

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