tolong dijawab no. 11-19!! please pake cara!

[tex]11. \\ \frac{1}{2} (4x - 5) = \frac{1}{4} x + 3 \frac{1}{2} \\ 4x - 5 = \frac{1}{2}x + 3 \\ 4x - \frac{1}{2} x = 3 + 5 \\ 4x - \frac{1}{2} x = 8 \\ 8x - x = 16 \\ 7x = 16 \\x = \frac{16}{7} \\ x = 2 \frac{2}{7} \\ \\ 12. \\ \frac{1}{6} (3x + 1) + \frac{1}{3} (x - 2) = 1 \frac{1}{6} \\ \frac{1}{2} x + \frac{1}{6} + \frac{1}{3} x - \frac{2}{3} = \frac{1}{6} \\ \frac{1}{2} x + \frac{1}{3} x - \frac{2}{3} = 0 \\ 3x + 2x - 4 = 0 \\ 5x - 4 = 0 \\ 5x = 4 \\ x = \frac{4}{5} \\ \\ 13. \\ \frac{3}{4} (x + 4) - \frac{2}{3} ( \frac{3}{4} - x) = \frac{1}{2} \\ \frac{3}{4} x + 3 - \frac{1}{2} + \frac{2}{3} x = \frac{1}{2} \\ \frac{3}{4} x + \frac{5}{2} + \frac{2}{3} x = \frac{1}{2} \\ 9x + 30 + 8x = 6 \\ 17x + 30 = 6 \\ 17x = 6 - 30 \\ 17x = - 24 \\ x = - \frac{24}{17} \\ x = 1 \frac{7}{17} \\ \\ 14. \\ \frac{1}{2} (2x - 5) + \frac{2}{3} (6 - x) = \frac{5}{6} x \\ x - \frac{5}{2} + 4 + \frac{2}{3} x = \frac{5}{6} x \\ x + \frac{3}{2} + \frac{2}{3} x = \frac{5}{6} x \\ 6x + 9 + 4x = 5x \\ 10x + 9 = 5x \\ 10 - 5x = - 9 \\ 5x = - 9 \\ x = - \frac{9}{5} \\ x = - 1 \frac{4}{5} \\ \\ 15. \\ \frac{y + 4}{4} - \frac{3y - 9}{7} = \frac{1}{2} \\ 7(y + 4) - 4(3y - 9) = 14 \\ 7y + 28 - 12y + 36 = 14 \\ - 5y + 64 = 14 \\ - 5y = 14 - 64 \\ - 5y = - 50 \\ y = 10 \\ \\ 16. \\ \frac{4 - y}{2} - \frac{y + 1}{3} = \frac{1}{4} \\ 6(4 - y) - 4(y + 1) = 3 \\ 24 - 6y - 4y - 4 = 3 \\ 20 - 10y = 3 \\ - 10y = 3 - 20 \\ - 10y = - 17 \\ y = \frac{17}{10} \\ y = 1 \frac{7}{10} \\ \\ 17. \\ \frac{y + 3}{4} + \frac{1 - 2y}{5} = \frac{y - 5}{10} \\ 5(y + 3) + 4(1 - 2y) = 2(y - 5) \\ 5y + 15 + 4 - 8y = 2y - 10 \\ - 3y + 19 = 2y - 10 \\ - 3y - 2y = - 10 - 19 \\ - 5y = - 29 \\ y = \frac{29}{5} \\ y = 5 \frac{4}{5} \\ \\ 18. \\ \frac{4y + 2}{3} + \frac{2y + 1}{2} = \frac{6y + 3}{4} \\ 4(4y + 2) + 6(2y + 1) = 3(6y + 3) \\ 16y + 8 + 12y + 6 = 18y + 9 \\ 28y + 14 = 18y + 9 \\ 28y - 18y = 9 - 14 \\ 10y = - 5 \\ y = - \frac{5}{10} \\ y = - \frac{1}{2} \\ \\ 19. \\ \frac{2y - 3}{4} - \frac{ 3y + 4}{2} = \frac{4y + 2}{8} \\ 2(2y - 3) - 4(3y + 4) = 4y + 2 \\ 4y - 6 - 12y - 16 = 4y + 2 \\ 4y - 4y - 6 - 12y - 16 = 2 \\ - 6 - 12y - 16 = 2 \\ - 22 - 12y = 2 \\ - 12y = 2 + 22 \\ - 12y = 24 \\ y = - 2[/tex]