Matematika

Pertanyaan

jika 8 log (64^x x4)= 3-x maka nilai x=

1 Jawaban

  • 8 log (64^x x4)= 3-x
    8 log 64^x + 8 log 4 = 3-x
    2^3 log (2^6)^x + 2^3 log 2^2 = 3-x
    2^3 log 2^6x + 2/3 2log2 = 3-x
    6x/3 2log2 + 2/3 2log2 = 3-x
    6x/3 + 2/3 = 3 - x
    2x + x = 3 - 2/3
    3x = 9/3 - 2/3
    3x = 7/3
    x = 7/3 x 1/3
    x = 7/9

    Maaf kalau salah

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