b.(4y - 5)(y+3)=(2y+5)pangkat2

[tex](4y - 5)(y + 3) = (2y + 5)^{2} \\ 4y ^{2} + 12y - 5y - 2 = 4y^{2} + 10y + 10y +25 \\ 4y^{2}+7y - 2 = {4y}^{2} + 20y + 25 \\ {4y}^{2} - {4y}^{2} + 7y - 20y - 2 - 25 = 0 \\ - 13y - 27 = 0[/tex]