Diketahui {9,2p,17,12,q}={17,r,s,6,2}.Jika p-q=1 dan s=r+3 ,hasil dari r+p-(q+s) =
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Pertanyaan
Diketahui {9,2p,17,12,q}={17,r,s,6,2}.Jika p-q=1 dan s=r+3 ,hasil dari r+p-(q+s) =
1 Jawaban
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1. Jawaban Anonyme
{9,2p,17,12,q} = {17,r,s,6,2}
p - q = 1
2p = 6
p = 3
q = 2
s = r + 3
s = 12
r = 9
r + p - (q + s)
= 9 + 3 - (2 + 12)
= 12 - 14
= -2