Matematika

Pertanyaan

Diketahui {9,2p,17,12,q}={17,r,s,6,2}.Jika p-q=1 dan s=r+3 ,hasil dari r+p-(q+s) =

1 Jawaban

  • {9,2p,17,12,q} = {17,r,s,6,2}

    p - q = 1
    2p = 6
    p = 3
    q = 2

    s = r + 3
    s = 12
    r = 9

    r + p - (q + s)
    = 9 + 3 - (2 + 12)
    = 12 - 14
    = -2

Pertanyaan Lainnya