Assalamu'alaikum,, kaka ad yg tau rumus pecahan parsial tdk??? contoh soal'a : 6x² + 19x -11 / (x+1)(x² + 5x-2) mksii kaa

[tex]\displaystyle \frac{6x^2+19x-11}{(x+1)(x^2+5x-2)} = \frac{A}{x+1}+\frac{Bx+C}{x^2+5x-2} \\ \\ \frac{6x^2+19x-11}{(x+1)(x^2+5x-2)} = \frac{A(x^2+5x-2)+(Bx+C)(x+1)}{(x+1)(x^2+5x-2)} \\ \\ \frac{6x^2+19x-11}{(x+1)(x^2+5x-2)} = \frac{Ax^2+5Ax-2A+Bx^2+(B+C)x+C}{(x+1)(x^2+5x-2)} \\ \\ \frac{6x^2+19x-11}{(x+1)(x^2+5x-2)} = \frac{(A+B)x^2+(5A+B+C)x+(C-2A)}{(x+1)(x^2+5x-2)} \\ \\ A+B=6 \\ 5A+B+C=19 \\ C-2A=-11 \\ \\ $Didapat:$ \\ A=4 \\ B=2 \\ C=-3 \\ \\ $Maka:$[/tex]
[tex]\displaystyle \frac{6x^2+19x-11}{(x+1)(x^2+5x-2)} = \frac{4}{x+1}+\frac{2x-3}{x^2+5x-2}[/tex]