Jumlah deret geometri tak hingga dari 8 + 16/3 + 32/9 +.... adalah....

8 + 16/3 + 32/9 + ...
8 + 8 x 2/3 + 8 x 4/9 + ...
a = 8
r = 2/3
Maka,
[tex]\displaystyle S_\infty = \frac{a}{1-r}=\frac{8}{1-\frac{2}{3}}=\frac{8}{\frac{1}{3}} \\ S_\infty = 24[/tex]