2 dadu dilempar/ditos sebanyak 90 kali . Frekuensi harapan munculnya mata dadu berjumlah 9 adalah...kali A.10 B.12 C.16 D.18

Fh = p(k) × n
[tex] = \frac{4}{36 \: } \times 90[/tex]
= 10 (a)

titik sampel 2 dadu: 6 x 6 = 36
mata dadu berjumlah 9 = {(3, 6), (4, 5), (5,4), (6,3)} → ada 4
peluang = 4/36 = 1/9

FREKUENSI HARAPAN =
[tex] \frac{1}{9} \times 90 = 10 \: kali[/tex] (A)