selesaian dari sistem persamaan 3×+2y-4=0 dan ×-3y-5=0 adalah

3x+2y-4 = 0 (dikali 1)
x-3y-5 = 0 (dikali 3)

Eliminasi x
3x+2y-4 = 0
3x-9y-15 = 0
___________ -
11y+11 = 0
11y = -11
y = -11 : 11
y = -1

subs. y = -1 ke 3x+2y-4 = 0
3x+2y-4 = 0
3x+2(-1)-4 = 0
3x+(-2)-4 = 0
3x-2-4 = 0
3x = 2+4
x = 6 : 3
x = 2