Matematika

Pertanyaan

1.
[tex]5 \times > 4 \times + 9 = [/tex]
2.
[tex]15 \times + 2 \leqslant 12 \times + 11 = [/tex]

1 Jawaban


  • [tex]1.5x > 4x + 9 \\ = 5x - 4x > 9 \\ = x > 9 \\ \\ 2.15x + 2 \leqslant 12x + 11 \\ = 15x - 12x \leqslant 11 - 2 \\ = 3x \leqslant 9 \\ = x \leqslant \frac{9}{3} \\ x \leqslant 3 [/tex]
    semoga membantu....

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